#### Searching for an attay within a data set

```Hi,

I have 3 cells that contain a set of values, the total of which will always
be constant eg:
A             B            C
1       0             2             1

I have a table populated with all possible combinations of these numbers:

0      0      3      n1
0      1      2      n2
1      1      1      n3
0      2      1      n4
etc. etc.

There is a fourth column to the right of this table with a set of
unconnected (and not necessarily unique) numbers (n).

How can I search the full table for the single occurrence of the pattern in
cells A B and C and return the value in column 4 - n4 in this case?

Many thanks

Dave
```
 0
RiskyDave (49)
3/1/2007 9:32:05 AM
excel 39879 articles. 2 followers.

3 Replies
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```Dave,

In D1 write something like this: Not Found

In an other cell place this formula:

=INDIRECT("D" & 1*(SUMPRODUCT(ROW(A3:A6)*((A3:A6 & B3:B6 & C3:C6)=(A1 & B1 &
C1)))=0)+SUMPRODUCT(ROW(A3:A6)*((A3:A6 & B3:B6 & C3:C6)=(A1 & B1 & C1))))

But perhaps there is a more simple solution.

Jan

```
 0
jg8091 (25)
3/1/2007 10:23:50 AM
```Since your rows in your table are all unique combinations and since n1, ..., nx
are all numbers, you could use:

=sumproduct(--(a1=sheet2!a1:a64),
--(b1=sheet2!b1:b64),
--(c1=sheet2!c1:c64),
(sheet2!d1:d64))

If the rows were unique combinations, but the n1, ..., nx were strings, you
could use something like:

(saved from a previous post)

If you want exact matches for just two columns (and return a value from a
third), you could use:

=index(othersheet!\$c\$1:\$c\$100,
match(1,(a2=othersheet!\$a\$1:\$a\$100)*(b2=othersheet!\$b\$1:\$b\$100),0))

(all in one cell)

This is an array formula.  Hit ctrl-shift-enter instead of enter.  If you do it
correctly, excel will wrap curly brackets {} around your formula.  (don't type
them yourself.)

Adjust the range to match--but you can only use the whole column in xl2007.

This returns the value in othersheet column C when column A and B (of
othersheet) match A2 and B2 of the sheet with the formula.

And you can add more conditions by just adding more stuff to that product
portion of the formula:

=index(othersheet!\$d\$1:\$d\$100,
match(1,(a2=othersheet!\$a\$1:\$a\$100)
*(b2=othersheet!\$b\$1:\$b\$100)
*(c2=othersheet!\$c\$1:\$c\$100),0))

Risky Dave wrote:
>
> Hi,
>
> I have 3 cells that contain a set of values, the total of which will always
> be constant eg:
>          A             B            C
> 1       0             2             1
>
> I have a table populated with all possible combinations of these numbers:
>
> 0      0      3      n1
> 0      1      2      n2
> 1      1      1      n3
> 0      2      1      n4
> etc. etc.
>
> There is a fourth column to the right of this table with a set of
> unconnected (and not necessarily unique) numbers (n).
>
> How can I search the full table for the single occurrence of the pattern in
> cells A B and C and return the value in column 4 - n4 in this case?
>
> Many thanks
>
> Dave

--

Dave Peterson
```
 0
petersod (12005)
3/1/2007 1:24:12 PM
```Jan and Dave,

My thanks, these solutions worked a treat :-)

Dave

"Dave Peterson" wrote:

> Since your rows in your table are all unique combinations and since n1, ..., nx
> are all numbers, you could use:
>
> =sumproduct(--(a1=sheet2!a1:a64),
>             --(b1=sheet2!b1:b64),
>             --(c1=sheet2!c1:c64),
>               (sheet2!d1:d64))
>
> If the rows were unique combinations, but the n1, ..., nx were strings, you
> could use something like:
>
> (saved from a previous post)
>
> If you want exact matches for just two columns (and return a value from a
> third), you could use:
>
> =index(othersheet!\$c\$1:\$c\$100,
>    match(1,(a2=othersheet!\$a\$1:\$a\$100)*(b2=othersheet!\$b\$1:\$b\$100),0))
>
> (all in one cell)
>
> This is an array formula.  Hit ctrl-shift-enter instead of enter.  If you do it
> correctly, excel will wrap curly brackets {} around your formula.  (don't type
> them yourself.)
>
> Adjust the range to match--but you can only use the whole column in xl2007.
>
> This returns the value in othersheet column C when column A and B (of
> othersheet) match A2 and B2 of the sheet with the formula.
>
> And you can add more conditions by just adding more stuff to that product
> portion of the formula:
>
> =index(othersheet!\$d\$1:\$d\$100,
>    match(1,(a2=othersheet!\$a\$1:\$a\$100)
>           *(b2=othersheet!\$b\$1:\$b\$100)
>           *(c2=othersheet!\$c\$1:\$c\$100),0))
>
>
> Risky Dave wrote:
> >
> > Hi,
> >
> > I have 3 cells that contain a set of values, the total of which will always
> > be constant eg:
> >          A             B            C
> > 1       0             2             1
> >
> > I have a table populated with all possible combinations of these numbers:
> >
> > 0      0      3      n1
> > 0      1      2      n2
> > 1      1      1      n3
> > 0      2      1      n4
> > etc. etc.
> >
> > There is a fourth column to the right of this table with a set of
> > unconnected (and not necessarily unique) numbers (n).
> >
> > How can I search the full table for the single occurrence of the pattern in
> > cells A B and C and return the value in column 4 - n4 in this case?
> >
> > Many thanks
> >
> > Dave
>
> --
>
> Dave Peterson
>
```
 0
RiskyDave (49)
3/2/2007 9:35:05 AM
 Reply:

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