#### Removing characters from cell - help req'd please

```Hope someone can help me with this one....

I have text in column "A" a list of parts like the following.....

...nhg1234
..nhg1235.54
nhg3456
....nhg1253.7

Is thier anyway of removing the dots in front the part number?
I dont want the points moving after the the main part of the number.

TiA

mag()()

```
 0
11/25/2006 10:26:02 AM
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```Do you part numbers all start with nhg?

If yes, you could select column A
edit|Replace
what:  .n
with:  n
replace all

And keep hitting the replace all button until all are fixed.

"Mag()()" wrote:
>
> Hope someone can help me with this one....
>
> I have text in column "A" a list of parts like the following.....
>
> ..nhg1234
> .nhg1235.54
> nhg3456
> ...nhg1253.7
>
> Is thier anyway of removing the dots in front the part number?
> I dont want the points moving after the the main part of the number.
>
>
> TiA
>
> mag()()

--

Dave Peterson
```
 0
petersod (12005)
11/25/2006 12:55:09 PM
```Mag
You could use this UDF - it will work with any number

l = Len(x) \ 2
For i = 1 To l
c = Mid(x, i, 1)
If c = "." Then
x = Application.WorksheetFunction.Substitute(x, ".", "", i)
i = i - 1
End If
Next
End Function

Copy the function into a VB Module (ALT + F11, Insert, Module) and use like
any formula

Regards
Peter

"Mag()()" wrote:

> Hope someone can help me with this one....
>
> I have text in column "A" a list of parts like the following.....
>
> ...nhg1234
> ..nhg1235.54
> nhg3456
> ....nhg1253.7
>
> Is thier anyway of removing the dots in front the part number?
> I dont want the points moving after the the main part of the number.
>
>
> TiA
>
> mag()()
>
>
>
```
 0
BillyLiddel (193)
11/25/2006 1:06:01 PM
```The numbers begin with various letters and numbers.

I will have a with the module reply.

Thanks

"Dave Peterson" <petersod@verizonXSPAM.net> wrote in message
news:45683D2D.21C7112@verizonXSPAM.net...
>
> If yes, you could select column A
> edit|Replace
> what:  .n
> with:  n
> replace all
>
> And keep hitting the replace all button until all are fixed.
>
>
>
> "Mag()()" wrote:
>>
>> Hope someone can help me with this one....
>>
>> I have text in column "A" a list of parts like the following.....
>>
>> ..nhg1234
>> .nhg1235.54
>> nhg3456
>> ...nhg1253.7
>>
>> Is thier anyway of removing the dots in front the part number?
>> I dont want the points moving after the the main part of the number.
>>
>>
>> TiA
>>
>> mag()()
>
> --
>
> Dave Peterson

```
 0
11/25/2006 2:33:17 PM
```If there are no spaces in your part number, you could use a formula:

=SUBSTITUTE(TRIM(SUBSTITUTE(A1,"."," "))," ",".")

"Mag()()" wrote:
>
> The numbers begin with various letters and numbers.
>
> I will have a with the module reply.
>
> Thanks
>
> "Dave Peterson" <petersod@verizonXSPAM.net> wrote in message
> news:45683D2D.21C7112@verizonXSPAM.net...
> >
> > If yes, you could select column A
> > edit|Replace
> > what:  .n
> > with:  n
> > replace all
> >
> > And keep hitting the replace all button until all are fixed.
> >
> >
> >
> > "Mag()()" wrote:
> >>
> >> Hope someone can help me with this one....
> >>
> >> I have text in column "A" a list of parts like the following.....
> >>
> >> ..nhg1234
> >> .nhg1235.54
> >> nhg3456
> >> ...nhg1253.7
> >>
> >> Is thier anyway of removing the dots in front the part number?
> >> I dont want the points moving after the the main part of the number.
> >>
> >>
> >> TiA
> >>
> >> mag()()
> >
> > --
> >
> > Dave Peterson

--

Dave Peterson
```
 0
petersod (12005)
11/25/2006 3:28:53 PM
```Hi Ma

Here's my take on a possible code solution.  Stick it in a module and
with your code sheet being the active sheet, click Run

Sub test(
Dim rng As Rang
Dim c As Rang
Set rng = Range("A1:A" & Range("a65536").End(xlUp).Row
With CreateObject("vbscript.regexp"
myVar = Chr\$(133
.Pattern = "^[\." & myVar & "]+
.Global = Tru
For Each c In rn
If .test(c.Value) Then c.Value = .Replace(c.Value, ""
Next
End Wit
End Su

--
RichardScholla
-----------------------------------------------------------------------
RichardSchollar's Profile: http://www.officehelp.in/member.php?userid=524

Posted from - http://www.officehelp.i

```
 0
11/25/2006 3:51:21 PM
```Thanx Dave,
Worked a treat.

mag()()

"Dave Peterson" <petersod@verizonXSPAM.net> wrote in message
news:45686135.10E183F5@verizonXSPAM.net...
> If there are no spaces in your part number, you could use a formula:
>
> =SUBSTITUTE(TRIM(SUBSTITUTE(A1,"."," "))," ",".")
>
>
>
> "Mag()()" wrote:
>>
>> The numbers begin with various letters and numbers.
>>
>> I will have a with the module reply.
>>
>> Thanks
>>
>> "Dave Peterson" <petersod@verizonXSPAM.net> wrote in message
>> news:45683D2D.21C7112@verizonXSPAM.net...
>> >
>> > If yes, you could select column A
>> > edit|Replace
>> > what:  .n
>> > with:  n
>> > replace all
>> >
>> > And keep hitting the replace all button until all are fixed.
>> >
>> >
>> >
>> > "Mag()()" wrote:
>> >>
>> >> Hope someone can help me with this one....
>> >>
>> >> I have text in column "A" a list of parts like the following.....
>> >>
>> >> ..nhg1234
>> >> .nhg1235.54
>> >> nhg3456
>> >> ...nhg1253.7
>> >>
>> >> Is thier anyway of removing the dots in front the part number?
>> >> I dont want the points moving after the the main part of the number.
>> >>
>> >>
>> >> TiA
>> >>
>> >> mag()()
>> >
>> > --
>> >
>> > Dave Peterson
>
> --
>
> Dave Peterson

```
 0
11/25/2006 7:24:02 PM
```Hi Richard

very good - I had a macro as well.

Dim l As Integer, i As Integer, c
Dim tmp
For Each c In Selection
c.Select
l = Len(c) \ 2
tmp = c
For i = 1 To l
x = Mid(tmp, i, 1)
If x = "." Then
tmp = Application.WorksheetFunction.Substitute(tmp, ".", "", i)
i = i - 1
End If
Next i
c.Value = tmp
Next
End Sub

For interest maybe

Peter

"RichardSchollar" wrote:

>
> Hi Mag
>
> Here's my take on a possible code solution.  Stick it in a module and,
> with your code sheet being the active sheet, click Run.
>
> Sub test()
> Dim rng As Range
> Dim c As Range
> Set rng = Range("A1:A" & Range("a65536").End(xlUp).Row)
> With CreateObject("vbscript.regexp")
> myVar = Chr\$(133)
> ..Pattern = "^[\." & myVar & "]+"
> ..Global = True
> For Each c In rng
> If .test(c.Value) Then c.Value = .Replace(c.Value, "")
> Next c
> End With
> End Sub
>
>
> --
> RichardSchollar
> ------------------------------------------------------------------------
> RichardSchollar's Profile: http://www.officehelp.in/member.php?userid=5248
>
> Posted from - http://www.officehelp.in
>
>
```
 0
BillyLiddel (193)
11/25/2006 8:04:01 PM

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