#### Counting individual dates

```I have a column of dates, some dates are repeated, and I would like a count
of the number of separate dates.

My sample column:
1/1/05
1/1/05
1/2/05

I want my return to be 2, because I have 2 different dates.

Is there a way to do this?

Thanx!

```
 0
robin (55)
6/14/2005 10:57:07 PM
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```Try...

=SUMPRODUCT((A1:A100<>"")/COUNTIF(A1:A100,A1:A100&""))

Hope this helps!

In article <3FD3EE87-AFC2-4854-9E70-1E1155D5798F@microsoft.com>,
"Robin" <Robin@discussions.microsoft.com> wrote:

> I have a column of dates, some dates are repeated, and I would like a count
> of the number of separate dates.
>
> My sample column:
> 1/1/05
> 1/1/05
> 1/2/05
>
> I want my return to be 2, because I have 2 different dates.
>
> Is there a way to do this?
>
> Thanx!
```
 0
domenic22 (716)
6/14/2005 11:13:16 PM
```THANX Domenic... that did the trick!  Now, where can I go to understand that
formula?

"Domenic" wrote:

> Try...
>
> =SUMPRODUCT((A1:A100<>"")/COUNTIF(A1:A100,A1:A100&""))
>
> Hope this helps!
>
> In article <3FD3EE87-AFC2-4854-9E70-1E1155D5798F@microsoft.com>,
>  "Robin" <Robin@discussions.microsoft.com> wrote:
>
> > I have a column of dates, some dates are repeated, and I would like a count
> > of the number of separate dates.
> >
> > My sample column:
> > 1/1/05
> > 1/1/05
> > 1/2/05
> >
> > I want my return to be 2, because I have 2 different dates.
> >
> > Is there a way to do this?
> >
> > Thanx!
>
```
 0
robin (55)
6/15/2005 12:01:07 AM
```Assuming...

A1:  1/1/05
A2:  1/1/05
A3:
A4:  1/2/05

Formula...

=SUMPRODUCT((A1:A4<>"")/COUNTIF(A1:A4,A1:A4&""))

Here's how it breaks down...

(A1:A4<>"") returns the following array of values:

TRUE
TRUE
FALSE
TRUE

COUNTIF(A1:A4,A1:A4&"") returns the following array of numbers:

2
2
1
1

(A1:A4<>"")/COUNTIF(A1:A4,A1:A4&"") returns the following array of
numbers:

0.5
0.5
0
1

Note that the numerical equivalent of TRUE and FALSE is 1 and 0,
respectively. So the first array of values are divided by the second
array of values...

TRUE/2 -----> 0.5
TRUE/2 -----> 0.5
FALSE/1 ---->  0
TRUE/1 ----->  1

Then, lastly, SUMPRODUCT sums these values and returns 2.

Hope this helps!

In article <7004565A-C6A2-4CF2-881B-54D16C9430A9@microsoft.com>,
"Robin" <Robin@discussions.microsoft.com> wrote:

> THANX Domenic... that did the trick!  Now, where can I go to understand that
> formula?
>
> "Domenic" wrote:
>
> > Try...
> >
> > =SUMPRODUCT((A1:A100<>"")/COUNTIF(A1:A100,A1:A100&""))
> >
> > Hope this helps!
> >
> > In article <3FD3EE87-AFC2-4854-9E70-1E1155D5798F@microsoft.com>,
> >  "Robin" <Robin@discussions.microsoft.com> wrote:
> >
> > > I have a column of dates, some dates are repeated, and I would like a
> > > count
> > > of the number of separate dates.
> > >
> > > My sample column:
> > > 1/1/05
> > > 1/1/05
> > > 1/2/05
> > >
> > > I want my return to be 2, because I have 2 different dates.
> > >
> > > Is there a way to do this?
> > >
> > > Thanx!
> >
```
 0
domenic22 (716)
6/15/2005 3:04:14 AM
```Excellent breakdown explanation....

Never did understood the SUMPRODUCT() either... now, I guess I can use
this too!!

--
terabar
------------------------------------------------------------------------
terabar's Profile: http://www.excelforum.com/member.php?action=getinfo&userid=24272

```
 0
6/15/2005 5:58:55 AM
```This will give you a detailed explanation of the function and it's uses:

http://www.xldynamic.com/source/xld.SUMPRODUCT.html
--
HTH,

RD
==============================================
Please keep all correspondence within the Group, so all may benefit!
==============================================

"terabar" <terabar.1qnlyb_1118815517.5594@excelforum-nospam.com> wrote in
message news:terabar.1qnlyb_1118815517.5594@excelforum-nospam.com...
>
> Excellent breakdown explanation....
>
> Never did understood the SUMPRODUCT() either... now, I guess I can use
> this too!!
>
>
> --
> terabar
> ------------------------------------------------------------------------
> terabar's Profile:
http://www.excelforum.com/member.php?action=getinfo&userid=24272
>

```
 0
ragdyer1 (4060)
6/15/2005 6:02:13 PM

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