Acessing function with a DLL which has be loaded from another dll

I have A.dll and B.dll.

Assume that A.dll has following functions:

Assume that B.dll has following functions:

I am loading B.dll from function A1() in A.dll.After Loading B.dll i
make a call to B1().After executing the call the function returns to
beginning of A2.dll.

why is this so?

5/14/2007 11:25:18 AM
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Define "begining".  The word tends to make no sense in this context.

What you seem to be saying is that you have

void A1()
     HANDLE h = ::LoadLibrary(_T("B.DLL"));
     ...test for h==NULL, deal with error
    typedef void (*B1)() B1Proc;
    B1Proc B1;
    B1 = ::GetProcAddress(h, "B1");

if this is not what you are doing, please clarity.

On 14 May 2007 04:25:18 -0700, nani <> wrote:

>I have A.dll and B.dll.
>Assume that A.dll has following functions:
>Assume that B.dll has following functions:
>I am loading B.dll from function A1() in A.dll.After Loading B.dll i
>make a call to B1().After executing the call the function returns to
>beginning of A2.dll.
>why is this so?
Joseph M. Newcomer [MVP]
MVP Tips:
newcomer (15972)
5/14/2007 1:15:49 PM
nani wrote:
> I have A.dll and B.dll.
> Assume that A.dll has following functions:
> A1()
> A2()
> Assume that B.dll has following functions:
> B1()
> B2()
> I am loading B.dll from function A1() in A.dll.After Loading B.dll i
> make a call to B1().After executing the call the function returns to
> beginning of A2.dll.
> why is this so?

If a function returns to the wrong place it means the stack has been 
corrupted or misused.  (The return address is stored in the stack.) This 
occurs when the caller and callee do not use the same specifications for 
the function's calling convention and/or parameters.  Make sure that 
both DLLs use a shared .h file that defines the function signature. 
Also make sure that both DLLs are compiled with the same compiler in the 
same mode (debug or release).

Scott McPhillips [MVP VC++]

5/14/2007 1:19:34 PM

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