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is 3rd character in a cell a space?
Looking for a way to determine if the 3rd character in a cell is a
space. (Dealing with mailing lists; trying to isolate values which
are first initial-period- "space" last name.
Thank you for your thoughts.
Rick
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Rick
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12/21/2009 7:06:17 PM |
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Hi Rick,
This may help you.
=IF(MID(E26,3,1)=" ","Y","N")
HTH
Regards,
Howard
"Rick" <rickyhalding@gmail.com> wrote in message
news:c1ec1b82-8ddb-4613-8d64-832de1e51bf8@d10g2000yqh.googlegroups.com...
> Looking for a way to determine if the 3rd character in a cell is a
> space. (Dealing with mailing lists; trying to isolate values which
> are first initial-period- "space" last name.
> Thank you for your thoughts.
> Rick
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L
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12/21/2009 7:16:59 PM
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Try this:
=3DIF(MID(A1,3,1)=3D" ","Yes","No")
Hope this helps.
Pete
On Dec 21, 7:06=A0pm, Rick <rickyhald...@gmail.com> wrote:
> Looking for a way to determine if the 3rd character in a cell is a
> space. =A0(Dealing with mailing lists; trying to isolate values which
> are first initial-period- "space" last name.
> Thank you for your thoughts.
> Rick
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Pete_UK
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12/21/2009 7:17:18 PM
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Hi Rick
See if this can help:
=If(Mid(A1,3,1)=" ","Space","No Space")
Regards,
Per
"Rick" <rickyhalding@gmail.com> skrev i meddelelsen
news:c1ec1b82-8ddb-4613-8d64-832de1e51bf8@d10g2000yqh.googlegroups.com...
> Looking for a way to determine if the 3rd character in a cell is a
> space. (Dealing with mailing lists; trying to isolate values which
> are first initial-period- "space" last name.
> Thank you for your thoughts.
> Rick
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Per
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12/21/2009 7:18:49 PM
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This will return either TRUE or FALSE:
=MID(A1,3,1)=CHAR(32)
CHAR(32) is the standard space character.
--
Biff
Microsoft Excel MVP
"Rick" <rickyhalding@gmail.com> wrote in message
news:c1ec1b82-8ddb-4613-8d64-832de1e51bf8@d10g2000yqh.googlegroups.com...
> Looking for a way to determine if the 3rd character in a cell is a
> space. (Dealing with mailing lists; trying to isolate values which
> are first initial-period- "space" last name.
> Thank you for your thoughts.
> Rick
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T
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12/21/2009 7:20:13 PM
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On Dec 21, 1:18=A0pm, "Per Jessen" <per.jes...@mail.dk> wrote:
> Hi Rick
>
> See if this can help:
>
> =3DIf(Mid(A1,3,1)=3D" ","Space","No Space")
>
> Regards,
> Per
>
> "Rick" <rickyhald...@gmail.com> skrev i meddelelsennews:c1ec1b82-8ddb-461=
3-8d64-832de1e51bf8@d10g2000yqh.googlegroups.com...
>
>
>
> > Looking for a way to determine if the 3rd character in a cell is a
> > space. =A0(Dealing with mailing lists; trying to isolate values which
> > are first initial-period- "space" last name.
> > Thank you for your thoughts.
> > Rick- Hide quoted text -
>
> - Show quoted text -
Ya'll are great!
Rick
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Rick
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12/21/2009 7:22:51 PM
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