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How do I round up numbers when dividing?
What I am doing is in regards to money. I am dividing an amount between two
people and sometimes the amount can't be divided equally so I want to be able
to have the formula automatically adjust.
So for instance: $5000.23 divided by 2 does not divide equally.
So person A should get $2500.12
and person be should get $2500.13
The same thing goes for $523.00
Thanks.
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Utf
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12/16/2009 10:11:01 PM |
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> So for instance: $5000.23 divided by 2 does not divide equally.
> So person A should get $2500.12
> and person be should get $2500.13
If the total amount is in A1 and you want Person A and Person B amounts in
B1 and C1 respectively, then:
B1: =ROUND(A1/2,2)
C1: =A1 - B1
Note: When working with dollars-and-cents amount, it is always prudent to
round explicitly to avoid anomailies due to the way Excel does arithmetic.
So C1 should actually be =ROUND(A1-B1,2).
----- original message -----
"girlieinsd" wrote:
> What I am doing is in regards to money. I am dividing an amount between two
> people and sometimes the amount can't be divided equally so I want to be able
> to have the formula automatically adjust.
>
> So for instance: $5000.23 divided by 2 does not divide equally.
> So person A should get $2500.12
> and person be should get $2500.13
>
> The same thing goes for $523.00
>
> Thanks.
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Utf
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12/16/2009 10:24:02 PM
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5000.23 divided by 2 will always return 2500.12 when set to 2 decimal
places.
Give Person B a penny from your pocket.
530.00 divided by 2 returns 265.00 so won't cost you anything from your
pocket.
Gord Dibben MS Excel MVP
On Wed, 16 Dec 2009 14:11:01 -0800, girlieinsd
<girlieinsd@discussions.microsoft.com> wrote:
>What I am doing is in regards to money. I am dividing an amount between two
>people and sometimes the amount can't be divided equally so I want to be able
>to have the formula automatically adjust.
>
>So for instance: $5000.23 divided by 2 does not divide equally.
>So person A should get $2500.12
>and person be should get $2500.13
>
>The same thing goes for $523.00
>
>Thanks.
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Reply
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Gord
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12/16/2009 10:48:21 PM
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2 Replies
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