I am trying to do so, but it is not working.

My .bat file:
C:\Program Files\Microsoft Office\OFFICE11
E:\IT Dept\Access\database name.mdb /x Marco Name

Is this correct?

hi,

On 03.03.2010 20:44, lindag wrote:
> I am trying to do so, but it is not working.
>
> My .bat file:
> C:\Program Files\Microsoft Office\OFFICE11
> E:\IT Dept\Access\database name.mdb /x Marco Name
>
> Is this correct?
No, see

http://support.microsoft.com/kb/209207

You need to specifiy the Access executable, e.g.:

Set ACCESS = "C:\Program Files\Microsoft Office\Office10\msaccess.exe"
Set DATABASE = "E:\IT Dept\Access\database name.mdb"
Start %ACCESS% %DATABASE% /x MarcoName

btw, you also need the quotation marks as the path to the executable and 
the database file contains spaces:

http://www.microsoft.com/resources/documentation/windows/xp/all/proddocs/en-us/ntcmds_shelloverview.mspx?mfr=true


mfG
--> stefan <--

You know the answer, and if it was yes, you would not ask  :-)

The command line is about launching MSACCESS.EXE;
The syntax is also wrong in cases of spaces in the  path name, since space 
is a delimiter between arguments, and if memory serves, you need to use " ", 
or, maybe, easier, to have the path and msaccess.exe and of the 
databaseName.mdb file in the PATH variable;
The space in the macro name maybe a problem... as may any typo (Marco... the 
Italian explorer?    :-)    )


Vanderghast, Access MVP


"lindag" <lindag@burt-law.com> wrote in message 
news:44d8e7d2-12a9-4765-8969-062a7ab36783@g10g2000yqh.googlegroups.com...
>I am trying to do so, but it is not working.
>
> My .bat file:
> C:\Program Files\Microsoft Office\OFFICE11
> E:\IT Dept\Access\database name.mdb /x Marco Name
>
> Is this correct?