|
|
Extract characters from a string
I would like to extract characters from a string field. I tried this
function: left(info, 2), the extracted character would be "in".
However, info is actually a field name which contants 1A_Peter. What
I want to extract is 1A instead.
How can I solve this problem?
THX ~
|
|
0
|
|
|
|
Reply
|
edouardlo
|
7/30/2007 6:51:20 AM |
|
On Jul 30, 1:51 pm, edouar...@gmail.com wrote:
> I would like to extract characters from a string field. I tried this
> function: left(info, 2), the extracted character would be "in".
> However, info is actually a field name which contants 1A_Peter. What
> I want to extract is 1A instead.
> How can I solve this problem?
> THX ~
Hi, try use:
In Modules write this code:
Function Extractstring(ByVal InString As String) As String
If InStr(InString, "_") <> 0 Then
Extract1 = Left(InString, Len(InString) - InStr(InString, "_") -
1)
Else: Extractstring = InString
End If
End Function
In controlsource of textbox use: = Extractstring([info])
HTH
Luan
|
|
0
|
|
|
|
Reply
|
luan
|
7/30/2007 9:00:29 AM
|
|
On Jul 30, 4:00 pm, luan <luanhox...@gmail.com> wrote:
> On Jul 30, 1:51 pm, edouar...@gmail.com wrote:> I would like to extract characters from a string field. I tried this
> > function: left(info, 2), the extracted character would be "in".
> > However, info is actually a field name which contants 1A_Peter. What
> > I want to extract is 1A instead.
> > How can I solve this problem?
> > THX ~
>
> Hi, try use:
>
> In Modules write this code:
> Function Extractstring(ByVal InString As String) As String
> If InStr(InString, "_") <> 0 Then
> Extract1 = Left(InString, Len(InString) - InStr(InString, "_") -
> 1)
> Else: Extractstring = InString
> End If
> End Function
>
> In controlsource of textbox use: = Extractstring([info])
>
> HTH
> Luan
Hi, sorry there is typing mistake:
Function Extractstring(ByVal InString As String) As String
If InStr(InString, "_") <> 0 Then
Extractstring = Left(InString, Len(InString) - InStr(InString,
"_") - 1)
Else: Extractstring = InString
End If
End Function
;-)
Luan
|
|
0
|
|
|
|
Reply
|
luan
|
7/30/2007 9:03:40 AM
|
|
|
2 Replies
517 Views
(page loaded in 0.068 seconds)
|
|
|
|
|
|
|
|
|