#### Re: data return based on two criteria #2

```Hello,

Can I use the same formula for the below requirement?
Sheet1
Column A - Assembly numbers (numbers repeats)
Column B - prepart (numbers repeats)
Column C - prepart description (description repeats)
Sheet 2
Column A - assembly partnumber
Column b1 : Z1 - prepart description

I would like to return corresponding prepart number
Eg.
Data base

A		B		C

X		123		aaaaaa
Z		123		aaaaaa
A1		F002		aaaaaa
Z2		F002		aaaaaa
C3		456		bbbbbb
D2		856		cccccc
F2		589		dddddd

Result

A		B		C		d
1	Assembly	aaaaaa	bbbbbb	cccccc
2	X		123
3	Z		123
4	A1		F002
5	Z2		F002
6	C3				456
7	D2						856

Regards

Jimmy Joseph
```
 0
6/10/2006 10:39:35 AM
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```Chip Pearson has a way of extracting an arbitrary value with repeats:
http://cpearson.com/excel/lookups.htm

Look for "Arbitrary Lookups"

Jimmy Joseph wrote:
>
> Hello,
>
> Can I use the same formula for the below requirement?
> Sheet1
> Column A - Assembly numbers (numbers repeats)
> Column B - prepart (numbers repeats)
> Column C - prepart description (description repeats)
> Sheet 2
> Column A - assembly partnumber
> Column b1 : Z1 - prepart description
>
> I would like to return corresponding prepart number
> Eg.
> Data base
>
> A               B               C
>
> X               123             aaaaaa
> Z               123             aaaaaa
> A1              F002            aaaaaa
> Z2              F002            aaaaaa
> C3              456             bbbbbb
> D2              856             cccccc
> F2              589             dddddd
>
> Result
>
>         A               B               C               d
> 1       Assembly        aaaaaa  bbbbbb  cccccc
> 2       X               123
> 3       Z               123
> 4       A1              F002
> 5       Z2              F002
> 6       C3                              456
> 7       D2                                              856
>
> Regards
>
> Jimmy Joseph

--

Dave Peterson
```
 0
petersod (12004)
6/10/2006 11:16:31 AM
```I think I misunderstood.

The values in column A repeat as well as the values in column B and C.

But there are never multiple instances of the same set of 3 values.

With your value in A2 and C1:

=index(othersheet!\$b\$1:\$b\$100,
match(1,(\$a1=othersheet!\$a\$1:\$a\$100)
*(c\$1=othersheet!\$c\$1:\$c\$100),0))

(all in one cell)

This is an array formula.  Hit ctrl-shift-enter instead of enter.  If you do it
correctly, excel will wrap curly brackets {} around your formula.  (don't type
them yourself.)

Adjust the range to match--but you can't use the whole column.

You can ignore the error if there is no match or convert to values and
edit|replace to get rid of it or even hide it using conditional formatting.

Or modify the formula to check to see if there's a match.

===
I think that's what you meant....

Jimmy Joseph wrote:
>
> Hello,
>
> Can I use the same formula for the below requirement?
> Sheet1
> Column A - Assembly numbers (numbers repeats)
> Column B - prepart (numbers repeats)
> Column C - prepart description (description repeats)
> Sheet 2
> Column A - assembly partnumber
> Column b1 : Z1 - prepart description
>
> I would like to return corresponding prepart number
> Eg.
> Data base
>
> A               B               C
>
> X               123             aaaaaa
> Z               123             aaaaaa
> A1              F002            aaaaaa
> Z2              F002            aaaaaa
> C3              456             bbbbbb
> D2              856             cccccc
> F2              589             dddddd
>
> Result
>
>         A               B               C               d
> 1       Assembly        aaaaaa  bbbbbb  cccccc
> 2       X               123
> 3       Z               123
> 4       A1              F002
> 5       Z2              F002
> 6       C3                              456
> 7       D2                                              856
>
> Regards
>
> Jimmy Joseph

--

Dave Peterson
```
 0
petersod (12004)
6/10/2006 11:34:59 AM

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