#### Evaluation same, result different?

```I selected A22:A27 then input the following:
{=CHAR(97+ROW(A22:A27)-ROW(A22))}    CSE
Though I get a,b,c ... e,f in cells A22:A27, but if I evaluate going into
each of the cells in this range, the evaluator returns CHAR(97) always, but
then how come the resultant character changes? Any ideas?

```
 0
5/17/2007 6:23:11 PM
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```Thu, 17 May 2007 23:53:11 +0530 from dindigul <padhye.m@gmail.com>:
> I selected A22:A27 then input the following:
> {=CHAR(97+ROW(A22:A27)-ROW(A22))}    CSE
> Though I get a,b,c ... e,f in cells A22:A27, but if I evaluate going into
> each of the cells in this range, the evaluator returns CHAR(97) always, but
> then how come the resultant character changes? Any ideas?

The value of row(A22:A27) is 22 if it's not inside an array formula.

--
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
```
 0
5/17/2007 8:05:47 PM
```You need to select a single cell in the array, then just click the evaluate
button until it changes to restart in the evaluation box and it will end
with the letter

--
Regards,

Peo Sjoblom

news:%23ZtMvBLmHHA.4852@TK2MSFTNGP03.phx.gbl...
>I selected A22:A27 then input the following:
> {=CHAR(97+ROW(A22:A27)-ROW(A22))}    CSE
> Though I get a,b,c ... e,f in cells A22:A27, but if I evaluate going into
> each of the cells in this range, the evaluator returns CHAR(97) always,
> but then how come the resultant character changes? Any ideas?
>

```
 0
terre081 (3244)
5/17/2007 8:10:18 PM
```Would you be more comfortable with something like this *non*-array formula

=CHAR(97+ROWS(\$1:1)-1)

Entered *anywhere*, will return the alphabet as it's copied down.
--
Regards,

RD

---------------------------------------------------------------------------
Please keep all correspondence within the NewsGroup, so all may benefit !
---------------------------------------------------------------------------
news:%23ZtMvBLmHHA.4852@TK2MSFTNGP03.phx.gbl...
>I selected A22:A27 then input the following:
> {=CHAR(97+ROW(A22:A27)-ROW(A22))}    CSE
> Though I get a,b,c ... e,f in cells A22:A27, but if I evaluate going into
> each of the cells in this range, the evaluator returns CHAR(97) always,
> but then how come the resultant character changes? Any ideas?
>

```
 0
ragdyer1 (4060)
5/17/2007 8:18:30 PM
```My question was that even when the result is char(97) throughout, how come
the characters change from a to b to c ...? I do not want any alternate
"Ragdyer" <ragdyer@cutoutmsn.com> wrote in message
news:%2318SRDMmHHA.4032@TK2MSFTNGP02.phx.gbl...
> Would you be more comfortable with something like this *non*-array formula
>
> =CHAR(97+ROWS(\$1:1)-1)
>
> Entered *anywhere*, will return the alphabet as it's copied down.
> --
> Regards,
>
> RD
>
> ---------------------------------------------------------------------------
> Please keep all correspondence within the NewsGroup, so all may benefit !
> ---------------------------------------------------------------------------
> "dindigul" <padhye.m@gmail.com> wrote in message
> news:%23ZtMvBLmHHA.4852@TK2MSFTNGP03.phx.gbl...
>>I selected A22:A27 then input the following:
>> {=CHAR(97+ROW(A22:A27)-ROW(A22))}    CSE
>> Though I get a,b,c ... e,f in cells A22:A27, but if I evaluate going into
>> each of the cells in this range, the evaluator returns CHAR(97) always,
>> but then how come the resultant character changes? Any ideas?
>>
>
>

```
 0
5/17/2007 8:34:14 PM
```because the +ROWS(\$1:1)-1 is added to the 97

paste that part in the rows and see

dindigul wrote:
> My question was that even when the result is char(97) throughout, how come
> the characters change from a to b to c ...? I do not want any alternate
> "Ragdyer" <ragdyer@cutoutmsn.com> wrote in message
> news:%2318SRDMmHHA.4032@TK2MSFTNGP02.phx.gbl...
>
>>Would you be more comfortable with something like this *non*-array formula
>>
>>=CHAR(97+ROWS(\$1:1)-1)
>>
>>Entered *anywhere*, will return the alphabet as it's copied down.
>>--
>>Regards,
>>
>>RD
>>
>>---------------------------------------------------------------------------
>>Please keep all correspondence within the NewsGroup, so all may benefit !
>>---------------------------------------------------------------------------
>>news:%23ZtMvBLmHHA.4852@TK2MSFTNGP03.phx.gbl...
>>
>>>I selected A22:A27 then input the following:
>>>{=CHAR(97+ROW(A22:A27)-ROW(A22))}    CSE
>>>Though I get a,b,c ... e,f in cells A22:A27, but if I evaluate going into
>>>each of the cells in this range, the evaluator returns CHAR(97) always,
>>>but then how come the resultant character changes? Any ideas?
>>>
>>
>>
>
>

```
 0
birelan (531)
5/17/2007 8:47:43 PM
```It's really *not* strange behavior for certain array formulas.

Arrays are rectangular ranges of formulas OR values, that XL treats as a
single group.
Some array formulas return an array of results that can appear in *many
cells*.
Other formulas affect an entire array of cells, yet return the result to a
*single* cell.

As far as your question is concerned:
Say A1 to A5 contain prices.
B1 to B5 contain quantities.
In C1 you enter the formula:

=A1*B1

Copying this formula down to C5 results in 5 *different* formulas, one in
each cell.

Now, select D1 to D5, and enter this formula in D1, the cell in focus:

=A1:A5*B1:B5

And use CSE to enter it.

You see the exact same returns in each column (C & D),
BUT ... as you click in each cell in D1 to D5, you see the *same* formula.

XL is using a *single* formula to compute multiple results, in place of 5
individual formulas.

This is a case where XL is using *less* memory and storage with the array
formula, then is used by the 5 individual formulas.

There are many cases, of course, where array formulas use *more* of XL's
resources then regular formulas.
--
HTH,

RD

---------------------------------------------------------------------------
Please keep all correspondence within the NewsGroup, so all may benefit !
---------------------------------------------------------------------------

news:%23Z8i%23KMmHHA.2272@TK2MSFTNGP02.phx.gbl...
> My question was that even when the result is char(97) throughout, how come
> the characters change from a to b to c ...? I do not want any alternate
> "Ragdyer" <ragdyer@cutoutmsn.com> wrote in message
> news:%2318SRDMmHHA.4032@TK2MSFTNGP02.phx.gbl...
>> Would you be more comfortable with something like this *non*-array
>>
>> =CHAR(97+ROWS(\$1:1)-1)
>>
>> Entered *anywhere*, will return the alphabet as it's copied down.
>> --
>> Regards,
>>
>> RD
>>
>> ---------------------------------------------------------------------------
>> Please keep all correspondence within the NewsGroup, so all may benefit !
>> ---------------------------------------------------------------------------
>> "dindigul" <padhye.m@gmail.com> wrote in message
>> news:%23ZtMvBLmHHA.4852@TK2MSFTNGP03.phx.gbl...
>>>I selected A22:A27 then input the following:
>>> {=CHAR(97+ROW(A22:A27)-ROW(A22))}    CSE
>>> Though I get a,b,c ... e,f in cells A22:A27, but if I evaluate going
>>> into each of the cells in this range, the evaluator returns CHAR(97)
>>> always, but then how come the resultant character changes? Any ideas?
>>>
>>
>>
>
>

```
 0
ragdyer1 (4060)
5/18/2007 12:23:28 AM

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