#### not sure if I'm using the correct formula for the result I want #2

```I'm trying to calculate a 'low net' score. A persons 'actual score' minus
'their handicap' = 'low net' score.

I have this worksheet setup like this;

A4:A23 = list of names
Columns B-U have the weekly calculated low net scores
B4:U23 = the calculated 'low net' scores using this formula
=SUM(Scorecard!B4-Scorecard!Y4); (this is for player one)
Scorecard!B4 is player one's first week 'actual score', Scorecard!Y4 is
player one's calculated 'handicap'.

In Row B25:U25 I have this formula {=MIN(IF(B\$4:B\$23>0,B\$4:B\$23))}, to pull
the lowest score of all persons for that week.

My problem is this;
I'm getting the #DIV/0 error and I don't know how to get around that because
we do have occational zero's "0" for scores when people don't show up. The
error is coming from my "handicap" formula
=((SUM(B4:C4)/COUNTIF(B4:C4,">0"))-36)*0.8

I have two bits of data to work around;
How can I write a formula to work above zero AND ignore the #DIV/0 cells?
I'm referring to B25:U25 formula.

Thanks,

```
 0
6/17/2009 10:50:06 AM
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```Hi,

post.
--
If this helps, please click the Yes button.

Cheers,
Shane Devenshire

> I'm trying to calculate a 'low net' score. A persons 'actual score' minus
> 'their handicap' = 'low net' score.
>
> I have this worksheet setup like this;
>
> A4:A23 = list of names
> Columns B-U have the weekly calculated low net scores
> B4:U23 = the calculated 'low net' scores using this formula
> =SUM(Scorecard!B4-Scorecard!Y4); (this is for player one)
>   Scorecard!B4 is player one's first week 'actual score', Scorecard!Y4 is
> player one's calculated 'handicap'.
>
> In Row B25:U25 I have this formula {=MIN(IF(B\$4:B\$23>0,B\$4:B\$23))}, to pull
> the lowest score of all persons for that week.
>
> My problem is this;
> I'm getting the #DIV/0 error and I don't know how to get around that because
> we do have occational zero's "0" for scores when people don't show up. The
> error is coming from my "handicap" formula
> =((SUM(B4:C4)/COUNTIF(B4:C4,">0"))-36)*0.8
>
> I have two bits of data to work around;
> How can I write a formula to work above zero AND ignore the #DIV/0 cells?
> I'm referring to B25:U25 formula.
>
> Thanks,
>
>
>
>
>
>
>
```
 0
6/18/2009 3:52:01 AM
```SORRY!
I didn't mean to post twice...after sending, it got stuck in my outbox.
While trying to fix the issue I inadvertantly sent it twice.

"Shane Devenshire" <ShaneDevenshire@discussions.microsoft.com> wrote in
message news:E4483D62-15CA-469E-989C-C13059321C0F@microsoft.com...
> Hi,
>
> previous
> post.
> --
> If this helps, please click the Yes button.
>
> Cheers,
> Shane Devenshire
>
>
>
>> I'm trying to calculate a 'low net' score. A persons 'actual score' minus
>> 'their handicap' = 'low net' score.
>>
>> I have this worksheet setup like this;
>>
>> A4:A23 = list of names
>> Columns B-U have the weekly calculated low net scores
>> B4:U23 = the calculated 'low net' scores using this formula
>> =SUM(Scorecard!B4-Scorecard!Y4); (this is for player one)
>>   Scorecard!B4 is player one's first week 'actual score', Scorecard!Y4 is
>> player one's calculated 'handicap'.
>>
>> In Row B25:U25 I have this formula {=MIN(IF(B\$4:B\$23>0,B\$4:B\$23))}, to
>> pull
>> the lowest score of all persons for that week.
>>
>> My problem is this;
>> I'm getting the #DIV/0 error and I don't know how to get around that
>> because
>> we do have occational zero's "0" for scores when people don't show up.
>> The
>> error is coming from my "handicap" formula
>> =((SUM(B4:C4)/COUNTIF(B4:C4,">0"))-36)*0.8
>>
>> I have two bits of data to work around;
>> How can I write a formula to work above zero AND ignore the #DIV/0 cells?
>> I'm referring to B25:U25 formula.
>>
>> Thanks,
>>
>>
>>
>>
>>
>>
>>

```
 0
6/18/2009 7:24:49 PM

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