#### Adding amount from 1 colum depending on # piece amount in colum 2

```L8 through L14 has \$amount, N8 through N14 has # of pieces. I need N15 to
have the total \$amount.
Example

L8         N8
23.00     2
14.00     0
5.00       1

N!4
51.00
I have searched and found a few examples but had a lot more involvement
Thanks

Thanks
Mike
```
 0
Utf
3/17/2010 4:50:04 PM
excel.misc 78881 articles. 5 followers.

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```What you appear to be doing can be a very simple calculation of
=L8*N8+L9*N9+L10*N10 (in your given figures) but that is not a satisfactory
way to handle this problem.
You should be using a column which calculates the total value of each row
and then calculate the total at the bottom of the row.
So you would introduce a column P for instance - in P8 input  =l8*n8
Copy that down to the extent of your range and in P15 input =sum(P8:P14)
This allows you to extend the range downwards without ever having to rethink
--
Russell Dawson
Excel Student

"hotrodflatglass" wrote:

> L8 through L14 has \$amount, N8 through N14 has # of pieces. I need N15 to
> have the total \$amount.
> Example
>
> L8         N8
> 23.00     2
> 14.00     0
> 5.00       1
>
>              N!4
>              51.00
> I have searched and found a few examples but had a lot more involvement
> Thanks
>
>
>
> Thanks
> Mike
```
 0
Utf
3/17/2010 5:14:01 PM
```Russel N15 will have the total  depending the number I put in N8 column
--
Thanks
Mike

"Russell Dawson" wrote:

> What you appear to be doing can be a very simple calculation of
> =L8*N8+L9*N9+L10*N10 (in your given figures) but that is not a satisfactory
> way to handle this problem.
> You should be using a column which calculates the total value of each row
> and then calculate the total at the bottom of the row.
> So you would introduce a column P for instance - in P8 input  =l8*n8
> Copy that down to the extent of your range and in P15 input =sum(P8:P14)
> This allows you to extend the range downwards without ever having to rethink
> --
> Russell Dawson
> Excel Student
>
>
>
> "hotrodflatglass" wrote:
>
> > L8 through L14 has \$amount, N8 through N14 has # of pieces. I need N15 to
> > have the total \$amount.
> > Example
> >
> > L8         N8
> > 23.00     2
> > 14.00     0
> > 5.00       1
> >
> >              N!4
> >              51.00
> > I have searched and found a few examples but had a lot more involvement
> > Thanks
> >
> >
> >
> > Thanks
> > Mike
```
 0
Utf
3/17/2010 6:22:01 PM

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