How to return the primary key from a combo box
I have a table containing two columns Column 1: Primary key Column 2: Name. I want to create an unbound combo box that shows the name but returns the PK. I have these properties set: Control source: <is empty> Row source type: table/query Bound column: 1 Row source: <I have a select that returns the desired records> In cboClient_AfterUpdate() I look at debug.print cboClient.Value and I see the name. I need the PK so I can construct the query for the next combo box. How do I get the PK Thanks for the help -- Message posted via http://www.accessmonster.com
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new2access123
2/20/2010 4:57:48 AM
access.modulesdaovba
1670 articles. 
0 followers.
5 Replies
981 Views
On Sat, 20 Feb 2010 04:57:48 GMT, "new2access123 via AccessMonster.com"
<u58027@uwe> wrote:
>I have a table containing two columns
>Column 1: Primary key
>Column 2: Name.
>
>I want to create an unbound combo box that shows the name but returns the PK.
>I have these properties set:
>
>Control source: <is empty>
>Row source type: table/query
>Bound column: 1
>Row source: <I have a select that returns the desired records>
>
>In cboClient_AfterUpdate() I look at debug.print cboClient.Value and I see
>the name. I need the PK so I can construct the query for the next combo box.
You need ColumnCount = 2, Bound Column 1, ColumnWidths property
0";1"
(or some other nonzero width for the name).
--
John W. Vinson [MVP]
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John
2/20/2010 6:42:12 AM
I have these propeerties set... row source : SELECT Client.Name FROM Client ORDER BY [Name]; ColumnCount: 2 Bound Column: 1 ColumnWidths: 0";2" In cboClient_AfterUpdate() I look at debug.print cboClient.Value and I see the still see the name from column 2 not the PK from column 1. Is there something I am missing? John W. Vinson wrote: >>I have a table containing two columns >>Column 1: Primary key >[quoted text clipped - 10 lines] >>In cboClient_AfterUpdate() I look at debug.print cboClient.Value and I see >>the name. I need the PK so I can construct the query for the next combo box. > >You need ColumnCount = 2, Bound Column 1, ColumnWidths property > >0";1" > >(or some other nonzero width for the name). > -- Message posted via AccessMonster.com http://www.accessmonster.com/Uwe/Forums.aspx/access-modules/201002/1
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new2access123
2/20/2010 7:10:29 AM
I see my error. Left out the PK from the SELECT field list. Thank ypu for the help. new2access123 wrote: >I have these propeerties set... >row source : SELECT Client.Name FROM Client ORDER BY [Name]; >ColumnCount: 2 >Bound Column: 1 >ColumnWidths: 0";2" > >In cboClient_AfterUpdate() I look at debug.print cboClient.Value and I see >the still see the name from column 2 not the PK from column 1. > >Is there something I am missing? > >>>I have a table containing two columns >>>Column 1: Primary key >[quoted text clipped - 7 lines] >> >>(or some other nonzero width for the name). -- Message posted via AccessMonster.com http://www.accessmonster.com/Uwe/Forums.aspx/access-modules/201002/1
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new2access123
2/20/2010 7:18:00 AM
John hit the nail on the head. See a visual sample here (Column Widths): http://office.microsoft.com/en-us/access/HA011730581033.aspx -- Ryan--- If this information was helpful, please indicate this by clicking ''Yes''. "John W. Vinson" wrote: > On Sat, 20 Feb 2010 04:57:48 GMT, "new2access123 via AccessMonster.com" > <u58027@uwe> wrote: > > >I have a table containing two columns > >Column 1: Primary key > >Column 2: Name. > > > >I want to create an unbound combo box that shows the name but returns the PK. > >I have these properties set: > > > >Control source: <is empty> > >Row source type: table/query > >Bound column: 1 > >Row source: <I have a select that returns the desired records> > > > >In cboClient_AfterUpdate() I look at debug.print cboClient.Value and I see > >the name. I need the PK so I can construct the query for the next combo box. > > You need ColumnCount = 2, Bound Column 1, ColumnWidths property > > 0";1" > > (or some other nonzero width for the name). > > > -- > > John W. Vinson [MVP] > . >
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Utf
2/20/2010 7:26:31 AM
On Sat, 20 Feb 2010 07:18:00 GMT, "new2access123 via AccessMonster.com"
<u58027@uwe> wrote:
>I see my error. Left out the PK from the SELECT field list. Thank ypu for
>the help.
<g> Yep... can't save what isn't there! Glad you got it working.
--
John W. Vinson [MVP]
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John
2/20/2010 8:24:48 PM
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Hi, Getting crazy with the XslTransform Class. I'm trying to transform an xml string with an xsl string with the following code : 'Create the XslTransform object and load the stylesheet. Dim oXslXmlReader As XmlTextReader = New XmlTextReader(MyXslString, XmlNodeType.Document, Nothing) Dim oXslXslTransform As XslTransform = New XslTransform oXslXslTransform.Load(oXslXmlReader, Nothing, Nothing) 'Load the xml to transform. Dim OXmlReader As XmlTextReader = New XmlTextReader(MyXmlString, XmlNodeType.Document, Nothing) Dim xPathDoc As XPathDocument = New XPathDocument(OXmlReader, Xml...
One of the product keys is not valid
Version: 2008 Operating System: Mac OS X 10.5 (Leopard) Processor: Intel Hi! I just installed the Office Mac Home and Student version in my MacBook and my husband tried the second product key on his IMac, but got a message saying the product key is not valid. We tried with the third key and it worked. The thing is I'm allowed to use the three of them but I can only use two. Of course, now we both have the software installed, but we still want access to the third key. We entered the numbers a couple of times, checking they were right. Any ideas? Thanks! Maria_O@officeformac.com wrote: &g...